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util.poll: Expose API (epoll or select) used

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Could he handy to know for debugging or decisions
This commit is contained in:
Kim Alvefur 2022-02-27 14:36:43 +01:00
parent 22d734e305
commit 04aa101da3
2 changed files with 11 additions and 6 deletions
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5
teal-src/util/poll.d.tl
View file

@ -19,6 +19,11 @@ local record lib
new : function () : state
ENOENT : integer
EEXIST : integer
enum api_backend
"epoll"
"select"
end
api : api_backend
end
return lib

12
util-src/poll.c
View file

@ -14,8 +14,10 @@
#if defined(__linux__)
#define USE_EPOLL
#define POLL_BACKEND "epoll"
#else
#define USE_SELECT
#define POLL_BACKEND "select"
#endif
#ifdef USE_EPOLL
@ -31,12 +33,7 @@
#include <lualib.h>
#include <lauxlib.h>
#ifdef USE_EPOLL
#define STATE_MT "util.poll<epoll>"
#endif
#ifdef USE_SELECT
#define STATE_MT "util.poll<select>"
#endif
#define STATE_MT "util.poll<" POLL_BACKEND ">"
#if (LUA_VERSION_NUM == 501)
#define luaL_setmetatable(L, tname) luaL_getmetatable(L, tname); lua_setmetatable(L, -2)
@ -487,6 +484,9 @@ int luaopen_util_poll(lua_State *L) {
push_errno(EEXIST);
push_errno(ENOENT);
lua_pushliteral(L, POLL_BACKEND);
lua_setfield(L, -2, "api");
}
return 1;
}