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prosodyctl: Corrected output printed by the remove command

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This commit is contained in:
João Duarte 2019-07-23 07:21:08 -07:00
parent c21b60857f
commit 9da5559197
1 changed files with 2 additions and 2 deletions
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prosodyctl
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@ -151,12 +151,12 @@ function commands.remove(arg)
-- I'm considering the flag is the first, but there can be many flags
if arg[1] and arg[1]:sub(1, #flag) == flag then
local dir = arg[1]:match("=(.+)$")
print("Removing module "..arg[2].." at "..dir..", from luarocks repo")
print("Removing module "..arg[2].." at "..dir)
-- These extra double brackets allow us to correctly process names with spaces
os.execute("luarocks remove --tree='"..dir.."' "..arg[2])
return 0;
else
print("Removing "..arg[1].." from ./plugins")
print("Removing "..arg[1].." from "..prosody.paths.plugins)
os.execute("luarocks --tree='"..prosody.paths.plugins.."' remove "..arg[1])
print("Done!")
return 0;