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use largest received packet number in packet number inflation

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fixes #309
This commit is contained in:
Lucas Clemente 2016-08-30 20:47:36 +02:00
parent be68d653db
commit 5cf829f1df
2 changed files with 10 additions and 5 deletions
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7
session_test.go
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@ -464,22 +464,25 @@ var _ = Describe("Session", func() {
hdr = &PublicHeader{PacketNumberLen: protocol.PacketNumberLen6}
})
It("sets the lastRcvdPacketNumber", func() {
It("sets the {last,largest}RcvdPacketNumber", func() {
hdr.PacketNumber = 5
err := session.handlePacketImpl(nil, hdr, nil)
Expect(err).ToNot(HaveOccurred())
Expect(session.lastRcvdPacketNumber).To(Equal(protocol.PacketNumber(5)))
Expect(session.largestRcvdPacketNumber).To(Equal(protocol.PacketNumber(5)))
})
It("sets the lastRcvdPacketNumber, for an out-of-order packet", func() {
It("sets the {last,largest}RcvdPacketNumber, for an out-of-order packet", func() {
hdr.PacketNumber = 5
err := session.handlePacketImpl(nil, hdr, nil)
Expect(err).ToNot(HaveOccurred())
Expect(session.lastRcvdPacketNumber).To(Equal(protocol.PacketNumber(5)))
Expect(session.largestRcvdPacketNumber).To(Equal(protocol.PacketNumber(5)))
hdr.PacketNumber = 3
err = session.handlePacketImpl(nil, hdr, nil)
Expect(err).ToNot(HaveOccurred())
Expect(session.lastRcvdPacketNumber).To(Equal(protocol.PacketNumber(3)))
Expect(session.largestRcvdPacketNumber).To(Equal(protocol.PacketNumber(5)))
})
It("ignores duplicate packets", func() {